tag:blogger.com,1999:blog-8219113377173546175.post6645989819173766467..comments2023-11-07T13:29:54.725+00:00Comments on GT's Blog: C C++ CODE : Gauss elimination for solving linear equationsGThttp://www.blogger.com/profile/16923656636145211711noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-8219113377173546175.post-76783469224071996752019-02-09T17:23:51.610+00:002019-02-09T17:23:51.610+00:00this code is working superb...thanksthis code is working superb...thanksAnonymoushttps://www.blogger.com/profile/09439730191242582583noreply@blogger.comtag:blogger.com,1999:blog-8219113377173546175.post-75378083973151685862013-10-15T10:19:59.115+01:002013-10-15T10:19:59.115+01:001 -0.8 (-0.8)^2 (-0.8)^3
0 1 2(-0.8) 3(-0...1 -0.8 (-0.8)^2 (-0.8)^3<br />0 1 2(-0.8) 3(-0.8)^2 <br />1 -0.4 (-0.4)^2 (-0.4)^3<br />0 1 2(-0.4) 3(-0.4)<br /><br /><br />a0<br />a1<br />a2<br />a3<br /><br /><br />tan(-0.8)<br />sec^2(-0.8)<br />tan(-0.4)<br />sec^2(-0.4)<br /><br /><br />these are 3 matrices like Ax=B<br /><br />We have to find the values of x ie(a0,a1,a2,a3) using Gaussian methos<br /><br /><br />Please bro its urgent can u do that for meRFhttps://www.blogger.com/profile/09276532564559102377noreply@blogger.com