Deploying .war file to Apache Tomcat Server : Working way

Here i am going to describe the [MANUAL]working way to deploy your .war(web application archive) file to the Apache Tomcat Server.
Suppose you have your web application's war file ,say MyProject.war exported from Eclipse Netbeans or similar IDE.
Steps:
1.Copy this .war file to webapps folder TOMCAT_HOME directory e.g, C:\apache-tomcat\webapps\
2.Restart the server, >> run the startup.bat in folder C:\apache-tomcat\bin
3.If the error message such as
     JAVA_HOME not defined or CATALINA_HOME not defined
     Then follow these steps to setup these environment variables:

• Right-click the My Computer icon on your desktop and select 'Properties'.
• Click the 'Advanced' tab (Windows XP), click on Advance System Settings on Windows7.
  
• Click the 'Environment Variables' button.
• Under 'System Variables', click 'New'.
• Enter the variable name as JAVA_HOME.
• Enter the variable value as the installation path for the Java Development Kit. eg. C:\Program Files (x86)\Java\jdk1.6.0_20
• Repeat the process for CATALINA_HOME variable and enter installation path for Tomcat Server, eg. C:\apache-tomcat\webapps\
• Click 'OK'.
• Click 'Apply Changes'.
• Restart the Server >> run the startup.bat in folder C:\apache-tomcat\bin

4.Launch http://localhost:[PORT]/MyProject/ on the browser, (port number might be 8080 or 8400). And Make sure the work offline option is not checked.
5.If everything is ok, the Home page of your app will be loaded into browser
6.Enjoy :)

hibernate show sql & parameter to console

You need to configure it 2 places :

1) Configuration in log4j logger : add following lines in - log4j.properties file  :

log4j.logger.org.hibernate.SQL=DEBUG
log4j.logger.org.hibernate.type=TRACE

The first is equivalent to hibernate.show_sql=true, the second prints the bound parameters among other things.

2)Configuration in hibernate.cfg.xml :

<property name="show_sql">true</property>

TO Show Formatted SQL :<property name="format_sql">true</property>

java escape html string - code

1) StringEscapeUtils from Apache Commons Lang:

import static org.apache.commons.lang.StringEscapeUtils.escapeHtml;
// ...
String source = "The less than sign (<) and ampersand (&) must be escaped before using them in HTML";
String escaped = escapeHtml(source);

OR 

2) Use Spring's HtmlUtils.htmlEscape(String input) method.